Question

The total of the ages of A, B and C at
present is 90 years. Ten years ago,
the ratio of their ages was 1:2:3.
What is the age of B at present?
(a) 40 years
(b) 30 years
(© 20 years
(d) 18 years​

Answer 1

Answer:

Let their ages 10 years ago is x, 2x and 3x years.

10 + 2x + 10 + 3x + 10 = 90 hence x= 10

B’s present age = (2x + 10) =30 years

Step-by-step explanation:

B) 30 is the answer

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Answer 2

$\Large{\underline{\underline{\red{GiVen:-}}}}$

The Age of Father = 2 year more than five times of the age of the son.

The Sum of their age = 38 years.

$\Large{\underline{\underline{\green{To Find:-}}}}$

The Age of each of them.

$\Large{\underline{\underline{\red{SoLuTioN:-}}}}$

$\implies\sf{Let, \: the \: age \: of \: son \: = \: }{\textsf{\textbf{x}}} \\ \\ \implies\sf{As, \: the \: age \: of \: Father \: is \: 2 \: year \: more \: than \: five \: times \: of \: son \: age} \\ \\ \implies\sf{So, \: the \: age \: of \: father \: = \: }{\textsf{\textbf{5x + 2}}} \\ \\ \implies\sf{x + 5x + 2 = \: }{\textsf{\textbf{36}}} \\ \\ \implies\sf{6x + 2 = \: }{\textsf{\textbf{38}}} \\ \\ \implies\sf{6x = 38 - 2 = \: }{\textsf{\textbf{36}}} \\ \\ \implies\sf{x = \cancel{36/6}} \\ \\ \implies\sf{x = \: }{\textsf{\textbf{6}}}$

Value of x = 6.

Therefore,

The age of son = 6.

The age of father = 5(6) + 2 = 32.