The total particle concentration in 100 cm3 of 0.2 M Al2(SO4)3 solution is
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Write the equation for aluminium sulfate's dissociation (all the species are in aqueous solution)
Al2(SO4)3⇌2Al3++3SO2−4
Notice the 1 mole of aluminium sulfate produces
2
moles of aluminium cations and
3
moles of sulfate anions.
This means that, for a given volume of solution, the concentration of the sulfate anions will be three times larger than the concentration of aluminium sulfate.
Think of it like this - same volume, three times the number of moles in favor of the sulfate anion
→
3 times the concentration.
Thus,
CAl2(SO4)3=13⋅CSO2−4=13⋅0.22 M=0.073 M
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