Question

The total positive charge in a glass of water containing 180 gm of water is approximately:(a) 1.0 × 10⁷ coulomb(b) 6.03 × 10⁷ coulomb(c) 1.80 × 10⁷ coulomb(d) 1.20 × 10⁷ coulomb

Answer 1

b is the right answer

Answer 2

Answer:

The total positive charge in a glass of water containing 180 grams of water is approximately $(a )1.0 \times 10^{7} C$.

Step-by-step:

We know that, the number of molecules in $18 \mathrm{gm}$ of water $=6.02 \times 10^{23}$

$\therefore$ Number of molecules in $180 \mathrm{gm}$ of water $=6.02 \times 10^{23} \times \frac{180}{18}$

$=6.02 \times 10^{24}$

Also, The number of protons in a molecule of water $=10$

$\therefore$ The total number of protons $(\mathrm{n})=6.02 \times 10^{24} \times 10$

$=6.02 \times 10^{25}$

Now, the total charge $(q)= ne$

$\begin{aligned}&=6.02 \times 10^{25} \times 1.6 \times 10^{-19} \\&=0.96 \times 10^{7} \\&=\mathbf{1 . 0} \times 10^{7} \text { Coulomb (approximately) }\end{aligned}$

Hence, the total positive charge in a glass of water containing 180 grams of water is approximately $1.0 \times 10^{7}$ Coulomb.