The total pressure exerted by the gaseous mixture of 4 mol of A2, 2 mol of B2 and 6 mol of C enclosed in a vessel of 4L at 298K is
(a) 50 atm
(b) 73.4 atm
(c) 62.9 atm
(d) 33.6 atm
Answers
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Explanation:
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Answered by
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Answer:
pv=nRT
total moles = 4+2+6=12mol
P= 12*0.0821*298/4
P=73.4
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