Chemistry, asked by cuteprincess4119, 7 months ago

The total pressure exerted by the gaseous mixture of 4 mol of A2, 2 mol of B2 and 6 mol of C enclosed in a vessel of 4L at 298K is
(a) 50 atm
(b) 73.4 atm
(c) 62.9 atm
(d) 33.6 atm

Answers

Answered by suhanaananya
0

Explanation:

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Answered by brkrishgroup06
0

Answer:

pv=nRT

total moles = 4+2+6=12mol

P= 12*0.0821*298/4

P=73.4

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