Question

the total pressure exerted by the mixture of equal moles of two gases is 5*10³ Nm-²in a container of volume 2 litres at 273k. calculate the number of moles of the gases mixed

Answer 1

Hello mate,

● Answer-

0.0022 moles of each gas

0.0044 moles for mixture

● Explanation-

# Given-

P = 5×10^3 Pa

V = 2 L = 2×10^-3 m^3

T = 273 K

# Solution-

Let n be total no of moles of mixture.

According to ideal gas equation,

PV = nRT

5×10^3 × 2×10^-3 = n × 8.314 × 273

n = 10 / (8.314×273)

n = 0.0044

No of moles of each gas will be half i.e. 0.0044/2 = 0.0022 moles.

Hope this helps...