the total ratio of PE:KE:TE of an orbiting satellite is
Answers
Answered by
1
Answer:
ANSWER
The kinetic energy of a satellite revolving at a height 'h' from Earth's surface is:
KE=
2(R+h)
GMm
Potential energy is:
PE=−
(R+h)
GMm
So,
PE
KE
=−
2
1
Answered by
5
Explanation:
the total ratio of PE:KE:TE of an orbiting satellite is -2 : 1 : -1
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by the way , R u 9th ?
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