Question

The total resistor of two resistor is 2 ohm when they are connected parallel and 4 when they are connected in series find the value of R1 and R2

Answer 1

Answer:

Explanation:

When they are connected in parallel:-

The resistors are of 2 Ω, then this will be as:-

$\sf{\dfrac{1}{R_1} = \dfrac{1}{2} + \dfrac{1}{2}}$

This is the general formulation in case of Parallel combination.

$\sf{\dfrac{1}{R_1} = \dfrac{1 + 1}{2}}$

$\sf{\dfrac{1}{R_1} = 1}$

$\sf{R_1 = 1 \ \Omega}$

Now, we need the connection in series, this will be as:-

$\sf{R_2 = 4 + 4}$

This is the general formulation of series combination.  

$\sf{R_2 = 8 \ \Omega}$

Now, we have found the values of R1 and R2 as 1 ohm and 8 ohms respectively.

So, 1 ohm and 8 ohms are the required answer.

Answer 2

Answer:

I dont khow

Explanation:

please ask again