Math, asked by vamshimadhav03, 5 months ago

.
The total sale (in '000 rupees) of a particular item in shop, on 10 consecutive days, is
reported by a clerk as, 35-00, 29.60, 38-00, 30-00, 40-00, 41-(00), 42-0), 45-00), 3.60, 3.80. Calculate the
average. Later it was found that there was a number 10.00 in the machine and the reports of 4th
to 8th days were 10.00 more than the true values and in the last 2 days he put a decimal in the
wrong place thus for example 3.60 was really 36-0. Calculate the truc mean value.​

Answers

Answered by amitnrw
0

Given : The total sales (in 000 rupees) of a particular item in a shop on 10 consecutive days is reported by a clerk as follows

35.00, 29.60, 38.00, 30.00, 40.00, 41.00, 42.00, 45.00, 3.60, 3.80

Later it was found that reports of the 4th and 8th days were 10.00 more than the true values

and that in the last two days the clerk put a decimal wrongly one place to the left.

To Find : Calculate the true mean value of sale

Solution:

S. No.  Noted         TRUE Values

1            35.00             35.00     No change

2           29.60            29.60     No change

3           38.00             38.00     No change

4           30.00             20.00   as noted was 10 more than true

5            40.00            40.00      No change  

6           41.00              41.00     No change

7           42.00              42.00     No change

8            45.00             35.00  as noted was 10 more than true

9           3.60              36.00  as put a decimal wrongly one place to the left.

10           3.80             38.00  as put a decimal wrongly one place to the left.

                                 354.6

true mean value of sale = 354.6/10  = 35.46  (in 000 rupees)

= 35460  Rs

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