the total surface area of a cone having its slant height 9 dm and diameter of its base 24 dm
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Answered by
18
Hi Mate!!!
Total surface are of cone having base radius r and slant height L is
( πr² ) + π × × L
Exp :-
r = 24 / 2 = 12dm
L = 9dm
=>
π ( 12 )² + π × 12 × 9
=>
π ×12 { 12 + 9 }
=>
π ×12 { 21 }
=>
( 22 / 7 ) × 12 × 21
=>
22 × 12 × 3
= 792dm²
1 dm = ( 1 / 10 )m
=>
1 dm² = ( 1 / 10² )m²
=>
792dm² = 792 / 10² m²
= 7.92m²
Have a nice time.
Total surface are of cone having base radius r and slant height L is
( πr² ) + π × × L
Exp :-
r = 24 / 2 = 12dm
L = 9dm
=>
π ( 12 )² + π × 12 × 9
=>
π ×12 { 12 + 9 }
=>
π ×12 { 21 }
=>
( 22 / 7 ) × 12 × 21
=>
22 × 12 × 3
= 792dm²
1 dm = ( 1 / 10 )m
=>
1 dm² = ( 1 / 10² )m²
=>
792dm² = 792 / 10² m²
= 7.92m²
Have a nice time.
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Answered by
1
Answer:
Hi mate here is your answer.
Step-by-step explanation:
Total surface are of cone having base radius r and slant height L is
( πr² ) + π × × L
Exp :-
r = 24 / 2 = 12dm
L = 9dm
=>π ( 12 )² + π × 12 × 9
=>π ×12 { 12 + 9 }
=>π ×12 { 21 }
=>( 22 / 7 ) × 12 × 21
=>22 × 12 × 3
= 792dm²
1 dm = ( 1 / 10 )m
=>1 dm² = ( 1 / 10² )m²
=>792dm² = 792 / 10² m²
= 7.92m²
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