Question

The total surface area of a cuboidal room whose length is twice the breadth is _________​

Answer 1

Given: (l+b+h), d1, d2, d3, d4

To find: TSA=2(lb+bh+hl)=?

Solution:

on the face ABCD, by Pythagoras theorem,

AC*AC = AB*AB+BC*BC = l^2 +b^2

Now, in triangle ACG,

AG= d1

BC= h

By pythogoras,

AG*AG = GC*GC + CA*CA

=> d1^2 = h^2 + l^2 + b^2……………………….eqn 1

Now, since

So,

since, 2(lb+bh+hl) is total surface area,

so putting values of (l+b+h) and eqn1 in it and then solving it, TSA can be found

Answer 2

Answer:

2(2h2+3bh)

please mark as brainliest answer