Question

The total surface area of a cylinder is 6512 cm2 and the circumference of its base is 88cm. Find i.Its radius ii.Its volume

Answer 1

here you go ☆☆

▪TSA of cylinder = 6512

▪circumference of base = 88

1.

▪2 ×22/7 ×r = 88

$r = 88 \times \frac{1}{2} \times \frac{7}{22}$

▪r = 14

hope it helps you........

Answer 2

Answer:

Hello mate..

Here is your answer...

Step-by-step explanation:

circumference of the base = 2πr = 88 cm.

2πr = 88

r = 88*7/2*44

r = 14 cm.

T.s.a = 2π r(r+h)

6512= 2*22/7*14(14+h)

6512= 88(14+h)

6512= 1232+88h

6512-1232=88h

5280 = 88h

h = 5280/88

h = 60 cm

vol. of cylinder = π*r^2*h

= 22/7*(14)^2*60

= 22/7*196*60

= 36960 cm^3

Hope this helped u .

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