The total surface area of a cylinder whose
height is twice the radius is
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Answer:
let r be the radius and h be the height of a cylinder
given;h=2r
we know that total surface area of a cylinder =2*pi*r*h+2*pi*r^2
=2*pi*r*(2r)+2*pi*r^2
=4*pi*r^2+2*pi*r^2
=6*pi*r^2
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