Question

The total surface area of a frustum-shaped glass tumbler is (R1>R2)
(A)
$\pi$

(B) (r +12) +ni riz
(C) Irh (x + 1 2 + 1712)
(Dy ſh² + (0g - Iz)?
and as a product of its prime factors as​

Answer 1

Answer:

ans is b

Step-by-step explanation:

TSA of frustrum of a tumbler is

CSA of frustrum+ base area only

no top area because tumbler is open at top so top is not counted

Answer 2

answer 9 . option (b)

answer 10. option (d)

Step-by-step explanation:

answer 9 .

here $r_1>r_2$

the total surface area of the frustum of glass = curved surface area of frustum + base of the glass

therefore ,

TSA of frustum of glass  = $\pi l (r_1+r_2)+\pi r_2^2$

hence , option (b)

answer 10 .

given number = 120

factors = 2×2×2×3×5

therefore , product of prime factors is 2³×3×5

hence , option (d)

#Learn more:

Volume of frustum,curved surface area of frustum,total surface area of frustum

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