the total surface area of a hollow cylinder whose external and internal radii are 4 cm and 3 cm
respectively and height is 14 cm.
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2
Answer:
660cm2
Step-by-step explanation:
Given internal radius r=3 cm
External radius R=(3+1) cm (Since thickness is 1 cm)
∴ Total surface area =2π(R+r)(h+R−r)
==2×
7
22
×(4+3)(14+4−3)=
7
44
×7×15=660cm
2
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