The total surface area of a one sided open cuboid whose height is a breadth is double of the height and length is double of the breath will be
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Answer:
4h² + 8bh
Step-by-step explanation:
According to question, the cuboid is one-sided open.
So, the total surface area will be:-
lb + 2(bh+hl) .........(i)
Given that breadth is double of the height:-
b= 2h
Also, it is given that length is double the breadth:-
l = 2b
putting the value of l and b in expression (i), we get:-
2b×2h + 2(2h×h + h×2b) = 4bh + 2(2h² + 2bh)
= 4bh +4h² + 4bh
= 4h² + 8bh
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