Question

The total surface area of a rectangular block is 1097 cm². What is the area of four sides of the block,if length is 19 cm
and the width is 16 cm?

539 cm²
439 cm²
488.6 cm²
793 cm²​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Given data : The total surface area of a rectangular block is 1097 cm². Length of cuboid is 19 cm and width of cuboid is 16 cm.

To find : The area of four sides of a rectangular block.

Solution : Assume that the rectangular block is cuboid, now

{According to given}

→ Length of cuboid, L = 19 cm

→ Width of cuboid, W = 16 cm

→ Heighr of cuboid, H = ?

→ Surface area of cuboid = 1097 cm²

Now, by formula :

→ Surface area of cuboid

= 2 * L * W + 2 * L * H + 2 * H * W

→ 1097 = 2 * 19 * 16 + 2 * 19 * H + 2 * H * 16

→ 1097 = 608 + 38 * H + 32 * H

→ 1097 = 608 + 70 * H

→ 1097 - 608 = 70 * H

→ 489 = 70 * H i.e.

→ H = 489/70 cm

Now, to find the area of four sides of the block.

→ Area of four side of block

= 2 * ( L + W ) * H

→ Area of four side of block

= 2 * ( 19 + 16 ) * 489/70

→ Area of four side of block

= 2 * 35 * 489/70

→ Area of four side of block

= 70 * 489/70

→ Area of four side of block

= 489 cm²

Here, we know 488.6 cm² approximately equal to 489 cm².

Answer : Hence, according to question the area of four sides of the block is 488.6 cm².

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