Question

the total surface area of a right circular cylinder is 2112cm2 and the radius of its base is 14cm . find the height​

Answer 1

$TSA=2\pi rh+2\pi r^2\\2112=2\pi r(h+r)\\2112=2\pi *14(h+14)\\\\h+14=\frac{2112*7}{2*14*22} \\\\h+14=\frac{1056}{2*22} \\\\h+14=\frac{528}{22}\\ \\h+14=24\\h=24-14\\h=10cm$

Answer 2

Answer:

TSA=2πrh+2πr

2

2112=2πr(h+r)

2112=2π∗14(h+14)

h+14=

2∗14∗22

2112∗7

h+14=

2∗22

1056

h+14=

22

528

h+14=24

h=24−14

h=10cm