The total surface area of a room is 346•5 m2 and if the area of four wall measures 204 m2,then find the surface area of the floor
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Hi ,
Area of the 4 walls of the
room = 204m²
Total surface area of the room =
346.5 m²
We know that ,
Let Area of the floor = area of the roof
= x m²
Area of the 4 walls of the room + 2 ×
floor area = total surface area of the
room
204 m² + 2xm² = 346.5 m²
2x = 346.5 - 204
2x = 142.5
x = 142.5/2
x = 71.25 m²
Therefore ,
surface area of the floor =x = 71.25m²
I hope this helps you
:)
Area of the 4 walls of the
room = 204m²
Total surface area of the room =
346.5 m²
We know that ,
Let Area of the floor = area of the roof
= x m²
Area of the 4 walls of the room + 2 ×
floor area = total surface area of the
room
204 m² + 2xm² = 346.5 m²
2x = 346.5 - 204
2x = 142.5
x = 142.5/2
x = 71.25 m²
Therefore ,
surface area of the floor =x = 71.25m²
I hope this helps you
:)
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