the total surface area of a solid right circular cylinder is 1540 m square . if its hieght is four times the radius of the base ,then find the h of the cylinder
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Given that TSA of a cylinder = 1540 m^2. and h = 4r ----- (1)
2 * pr * r(h + r) = 1540
2 * 22/7 * r(4r + r) = 1540 (Given that height is 4 times of radius)
2 * 22/7 * 5r^2 = 1540
44/7 * 5r^2 = 1540
r^2 = 49
r = 7cm.
Substitute r in (1), we get
Height h of the cylinder = 4 * r
= 28 cm.
Hope this helps!
2 * pr * r(h + r) = 1540
2 * 22/7 * r(4r + r) = 1540 (Given that height is 4 times of radius)
2 * 22/7 * 5r^2 = 1540
44/7 * 5r^2 = 1540
r^2 = 49
r = 7cm.
Substitute r in (1), we get
Height h of the cylinder = 4 * r
= 28 cm.
Hope this helps!
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