the total surface area of a solid right circular cylinder is 231cm2 it's curved surface area is 2/3of total surface determined the radius of its base and height
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the total surface area of cylinder =231cm2
=> 2πr(r+h)=231 cm2
=> 2πr2+2πrh=231 cm2--------(a)
its curved surface area is=2/3(231)cm2(given)
=> 2πrh=154 cm2 --------(b)
putting value of 2πrh from equ. (b) in equ. (a) we get
=> 2πr2+154=231
=>2πr2=231-154
=>2πr2=77
=>r2=77/(2π)
=> r2=12.25 (since π=22/7)
=> r=(12.25)1/2 cm = 3.5 cm
to find the value of h
now by putting the value of r=3.5cm in equ. (b) we get
=> 2πrh=154
=> 2(22/7)*3.5* h=154
=> 22h=154
=> h=154/22 cm = 7cm
=> 2πr(r+h)=231 cm2
=> 2πr2+2πrh=231 cm2--------(a)
its curved surface area is=2/3(231)cm2(given)
=> 2πrh=154 cm2 --------(b)
putting value of 2πrh from equ. (b) in equ. (a) we get
=> 2πr2+154=231
=>2πr2=231-154
=>2πr2=77
=>r2=77/(2π)
=> r2=12.25 (since π=22/7)
=> r=(12.25)1/2 cm = 3.5 cm
to find the value of h
now by putting the value of r=3.5cm in equ. (b) we get
=> 2πrh=154
=> 2(22/7)*3.5* h=154
=> 22h=154
=> h=154/22 cm = 7cm
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1
yes answer is 7 çorrect
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