the total surface area of a solid right circular cylinder is 1540 cm if the height is four times the radius of the base ,then find the height of the cylinder.
Answers
Answered by
85
H = 4r ( given)
TSA = 1540
PIE r ( r+ h) = 1540
Pie r ( r + 4r ) = 1540
Pie r ( 5r ) = 1540
Pie 5r^2 =1540
22/7×5r^2 =1540
110r^2/7= 1540
r^2= 1540×7/22
r^2 = 49
r= 7
H=4
H= 4×7
= 28
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Answered by
159
total surface area of cylinder = 2πr(r+h) = 1540
h = 4r
TSA = 2πr(r+4r)
TSA = 2πr(5r)
TSA = 10πr²
10πr² =1540
πr² =154
r² = 49
r = 7
h = 4r
h = 4 * 7
h = 28
h = 4r
TSA = 2πr(r+4r)
TSA = 2πr(5r)
TSA = 10πr²
10πr² =1540
πr² =154
r² = 49
r = 7
h = 4r
h = 4 * 7
h = 28
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