The total surface area of a tank in which the length, breadth, height are in the ratio 2:2:1 is 5.76 metre cube . Find the length of the tanks diagonal
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If the length, breadth and height are in the ratio 2:2:1 then the dimensions are 2x, 2x and x for some value of x. Therefore, in terms of x, the volume = (2x) * (2x) * x = 4x^3.
So 4x^3 = 5.76
x^3 = 5.76/4
x = 1.44
The dimensions of the box are (2×1.44), (2 * 1.44), 1.44
i.e. 2.88,2.88 and 1.44 cm.
Therefore its surface area =
2[(2.88×2.88) + (2.88×1.44) + (1.44×2.88)]
= 2(8.294 + 4.1472 + 4.1472)
= 1658.84m^2
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