the total surface area of cuboid is 40 m square and its later surface area is 26 m square find the area of the floor
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total surface area of the cuboid = 50 sq.m
lateral surface are of the cuboid = 26 sq.m
therefore
2(lb + lh + bh) - 2(lh + bh) = 50 - 26 sq.m
2lb = 24 sq.m
lb = 12 sq.m
so area of the floor = 12 sq.m
lateral surface are of the cuboid = 26 sq.m
therefore
2(lb + lh + bh) - 2(lh + bh) = 50 - 26 sq.m
2lb = 24 sq.m
lb = 12 sq.m
so area of the floor = 12 sq.m
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