Question

The total surface area of cylinder is 8448 sqcm.if the radius of its base is 28cm,what is it's height

Answer 1

Answer:

kya yaar bhai

2πr(h plus r) lagao aayega

Step-by-step explanation:

answer saree value udhar bhej do h chhod ke kaat pit do Aa jayega

Answer 2

Answer:

$\red { Height \: of \:the \: cylinder }\green {=20\:cm }$

Step-by-step explanation:

$Given \: radius \: of \: the \:base (r) = 28 \:cm$

$Let \: height \: of \: the \: cylinder = h \:cm$

$Total \: surface \: Area \:of \: cylinder = 8448\:cm^{2}$

$\implies 2\pi r( r+h) = 8448$

$\implies 2 \times \frac{22}{7} \times 28 ( 28+h) = 8448$

$\implies 28+h = \frac{ 8448 \times 7 }{2\times 22 \times 28 }$

$\implies 28 + h = 48$

$\implies h = 48 - 28 = 20 \:cm$

Therefore.,

$\red { Height \: of \:the \: cylinder }\green {=20\:cm }$

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