Math, asked by himanshubobby4204, 10 months ago

the total surface area of hollow cylinder which is open from both sides is 4620square cm area of base ring is 115.5 square cm and height is 7 cm. find the thickness of cylinder​

Answers

Answered by Anonymous
6

Step-by-step explanation:

Let the radii of outer and inner surfaces be R and r.

(I) TSA of hollow cylinder :

TSA = Outer CSA + Inner CSA + 2(Area of circular base)

➳ 4620 = 2πRh + 2πrh + 2π(R² - r²)

➳ 4620 = 2πh(R + r) + 2 × 115.5

➳ 4620 = 2πh(R + r) + 231

➳ 4620 - 231 = 2πh(R + r)

➳ 4389 = 2πh(R + r)

➳ 4389 = 2 × 22/7 × 7 × (R + r)

➳ 4389 = 44 × (R + r)

➳ 4389/44 = (R + r)

➳ 399/4 = (R + r) ...........[Equation (i)]

_____________________

(II) Area of base ring :

Area of base ring = π(R² - r²)

➳ 115.5 = 22/7(R² - r²)

➳ 115.5 × 7 = 22(R² - r²)

➳ 808.5/22 = R² - r²

➳ 8085/22 = R² - r²

➳ 147/4 = (R + r) (R - r).......[Equation (ii)]

____________________

Now, Substituting equation (I) in equation (II) we get,

➳ 147/4 = (R + r) (R - r)

➳ 147/4 = (399/4) (R - r)

➳ (R - r) = 399/147

➳ (R - r) = 7/19

(R - r) = 0.36842 cm

Therefore, the thickness of the cylinder is 0.36842 cm.

Answered by SarcasticL0ve
13

GivEn total surface area of hollow cylinder is 4620 cm²

Area of base ring is 115.5 cm².

Height of cylinder is 7 cm

We have to find, Thickness of cylinder.

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

☯ So, Let's radius of outer surface be R.

☯ And, Radius of inner surface be r.

⋆ We have,

Area of base ring = 115.5 cm²

Therefore,

➟ Area of base ring = π(R² - r²)

⋆ Putting values,

➟ 115.5 = 22/7(R² - r²)

➟ 115.5 × 7/22 = R² - r²

➟ 808.5/22 = R² - r²

➟ 8085/220 = R² - r²

➟ 147/4 = (R + r)(R - r) .....[eq. (1)]

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

Now we have to find TSA of hollow cylinder

➟ TSA = Outer CSA + Inner CSA + 2(Area of circular base)

➟ 4620 = 2πRh + 2πrh + 2(πR² - πr²)

➟ 4620 = 2πRh + 2πrh + 2π(R² - r)

⋆ Now, Putting values,

➟ 4620 = 2πh(R + r) + 2 × 115.5

➟ 4620 = 2πh(R + r) + 231

➟ 4620 - 231 = 2πh(R + r)

➟ 4389 = 2πh(R + r)

➟ 4389 = 2 × 22/7 × 7(R + r)

➟ 4389 = 2 × 22(R + r)

➟ 4389 = 44(R + r)

➟ 4389/44 = (R + r)

➟ 399/4 = (R + r) .....[eq. (2)]

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

Now, Putting value of eq(2) in eq(1),

➟ 147/4 = (339/4)(R - r)

➟ 147/4 × 4/339 = (R - r)

➟ (R - r) = 147/339

➟ (R - r) = 7/19

Therefore,

(R - r) = 0.36842 cm

⋆ We know that,

Thickness of cylinder = Outer radius - Inner Radius = (R - r)

The Thickness of Cylinder is 0.36842 cm.

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