Math, asked by virajrai870, 1 year ago

the total surface of a hemispherical shell when the outer radius is 2 cm and the inner radius is 1 cm is ​

Answers

Answered by RvChaudharY50
0

Answer:

TSA of hollow hemispherical ball = 3π[(r1)² - (r2)²]

= 3π(2²-1)² = 3*3.14*3 = 28.26cm² (Ans.)

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