. The total vapour pressure of a solution of methanol
and ethanol in an ideal solution is given by P =
135 a
+ 100 (where a = mole fraction of
methanol). Pure state vapour pressure of methanol
is
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Answered by
1
The total vapour pressure of a solution of methanol
and ethanol in an ideal solution is given by P =
135 a
+ 100 (where a = mole fraction of
methanol). Pure state vapour pressure of methanol is liquid
Answered by
0
Answer:
P=135a+100
let's take mole fraction a=1
Pmethanol =135(1)+100
Pmethanol=235ummg
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