Question

the total volume of 0.1 M KMnO4 solution that are needed to oxidize 100 mg each of ferrous oxalate and ferrous sulphate in a mixture in acidic medium is

Answer 1

Answer:

1 mole(144g) of FeC2O4FeC2O4 gives 3 moles of electrons to oxidize into Fe3+Fe3+ and CO2CO2 . So, 100 g gives100×3144=2.0833100×3144=2.0833 moles of elecrrons.

One mole of KMnO4KMnO4needs 5 moles of electrons in acidic medium to reduce to Mn2+Mn2+ .

So, to take the 2.0833 moles of electrons given out by Ferrous oxalate , we need 2.085=0.41672.085=0.4167 moles of KMnO4.KMnO4.

To find the volume of 0.1 M solution,which contains the required 0.4167 moles ,

V=0.41670.1=4.167LV=0.41670.1=4.167L

So, you need 4.167 L of 0.1 M potassium permanganate solution to oxidize 100grams of ferrous oxalate in acidic medium.