the total volume of dry gaseous product at stp when 3 moles of electron are transferd from anode to cathode in the electrolisis of water is
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Answer:
According to first law of faraday,
Ewt
Wt
=
F
Q
F
Q
= farady No.
∴ charge of 1 mol of electrons is equal to 1 farady.
Ewt
Wt
=
F
ne
∴Q=ne and n=4
mole×V.f.=
F
4F
mole×2=4
mols of H
2
O=2
Hence the two moles of H
2
O will decomposed into it's gaseous components
2H
2
O⟶2H
2
+O
2
2moles of H
2
(at cathode) and 1mol of O
2
(at anode) will produce.
moles=
22.4
v
So volume of H
2
and O
2
will be = 44.8+22.4 = 67.2
Explanation:
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