Question

The total wages of 6 men for 15 day work is Rs.23220. What will be the total wage of 15 men for 21 day work, if the additional 9 men take 3 times the wage than others?

Answer 1

Answer:

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Step-by-step explanation:

Let the required wages be Rs. x.

More men, More wages (Direct Proportion)

Less days, Less wages (Direct Proportion)

Men 6: 9 : : 2100:x

Days 15:12

Therefore (6 x 15 x x) = (9 x 12 x 2100)

x = (9 x 12 x 2100)/(6 x 15) = 2520

Hence the required wages are Rs. 2520.

Answer 2

The total wage of 15 men for 21 day work, if the additional 9 men take 3 times the wage than others is Rs 130032

Given : The total wages of 6 men for 15 day work is Rs.23220

To Find : The total wage of 15 men for 21 day work, if the additional 9 men take 3 times the wage than others

Solution : The total wage of 15 men for 21 day work, if the additional 9 men take 3 times the wage than others is Rs 130032

It is given that the total wages of 6 men for 15 day work is Rs.23220

we have to find the total wage of 15 men for 21 day work, if the additional 9 men take 3 times the wage than others

Now

6 men wages for 15 day us Rs 23220

6 men wage for 1 day is $\frac{23220}{15}$

Since the additional 9 men take 3 times the wage than others

So ,

9 men wage for 1 day is $\frac{23220}{15}$ × 3

6 men wages for 21 day (W1) is  $\frac{23220}{15}$ × 21  = $\frac{162540}{5}$

9 men wages for 21 day (W2) is  $\frac{23220}{15}$ × 21 × 3 = $\frac{487620}{5}$

So total wages of 15 men for 21 day is

W1 +W2

=  $\frac{162540}{5}$ + $\frac{487620}{5}$

= $\frac{650160}{5}$

= Rs 130032

So the total wage of 15 men for 21 day work, if the additional 9 men take 3 times the wage than others is Rs 130032

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