The traffic lights at three different road crossings change after every 48 sec,72 sec,108 sec respectively. if they change simultaneously at 8:20:00 hours, then they will change again simultaneously at
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Answer:
takethe hcf of the 48 72 and 108 and then mutiply it you get 432 and then divide it by 60 and you get the ans as 12 min and 7 sec
Step-by-step explanation:
hcf of 48= 2*2*2*2*3=
hcf of 72 = 2*2*2*3*3
hcf of 108= 2*2*3*3*3
lcm of 48,72,108 =432
432/60=7min and 12sec
so the light changes at 8:27:12
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