Math, asked by zameer12, 11 months ago

The traffic lights at three different roads crossing change after 48,72 and
108 s, respectively. If they change simultaneously at 7 am, then at what
time will they change simultaneously again?

Answers

Answered by Anonymous
5
REQUIRED TIME in s = LCM(48,72,108) = 432

Minutes = 420s = 7 min,

seconds = 432-420 = 12s

Required Time = 7 : 7 : 12 am

Anonymous: Thanks for that.
zameer12: for what
Anonymous: for marking brainliest
Answered by BrainlyPARCHO
0

 \large \green{  \fcolorbox{gray}{black}{ ☑ \:  \textbf{Verified \: answer}}}

If the traffic lights change simultaneously at 7 a.m, then they will change simultaneously again after the LCM of the duration i.e. 48 s, 72 s and 108 s.

LCM of these durations by prime factorisation

48 = 2 × 2 × 2 × 2 × 3 = 2⁴ × 3

72 = 2 × 2 × 2 × 3 × 3 = 2³ × 3²

108 = 2 × 2 × 3 × 3 × 3 = 2² × 3³

LCM of 48, 72 and 108 is 2⁴ × 3³ = 432 seconds.

Hence, They will change after 432 seconds i.e. 7 minutes 12 seconds.

The traffic lights will change after:

7 am + 7 minutes 12 seconds

07 : 07 : 12 am

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