The traffic lights at three different roads crossing change after 48,72 and
108 s, respectively. If they change simultaneously at 7 am, then at what
time will they change simultaneously again?
Answers
Answered by
5
REQUIRED TIME in s = LCM(48,72,108) = 432
Minutes = 420s = 7 min,
seconds = 432-420 = 12s
Required Time = 7 : 7 : 12 am
Minutes = 420s = 7 min,
seconds = 432-420 = 12s
Required Time = 7 : 7 : 12 am
Anonymous:
Thanks for that.
Answered by
0
If the traffic lights change simultaneously at 7 a.m, then they will change simultaneously again after the LCM of the duration i.e. 48 s, 72 s and 108 s.
LCM of these durations by prime factorisation
48 = 2 × 2 × 2 × 2 × 3 = 2⁴ × 3
72 = 2 × 2 × 2 × 3 × 3 = 2³ × 3²
108 = 2 × 2 × 3 × 3 × 3 = 2² × 3³
LCM of 48, 72 and 108 is 2⁴ × 3³ = 432 seconds.
Hence, They will change after 432 seconds i.e. 7 minutes 12 seconds.
The traffic lights will change after:
7 am + 7 minutes 12 seconds
07 : 07 : 12 am
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