The traffic police recorded the speed (in km/hr) of 10 motorists as 47, 53, 49, 60, 39, 42,55, 57, 52, 48. later on an error in recording instrument was found. Find the correct average speed of the motorists if the instrument recordesd 5 km/hr less in each case
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67
Solution:-
Given : Recorded speed (in km/hr) of the 10 motorists are 47, 53, 49, 60, 39, 42, 55, 57, 52, 48
recorded average speed (in km/hr) of 10 motorists
= (47 + 53 + 49 + 60 + 39 + 42 + 55 + 57 + 52 + 48)/10
= 502/10
= 50.2 km/hr
Now, the instrument recorded 5 km/hr less in each case.
So, corrected average speed = 50.2 + 5 = 55.2 km/hr
Answer.
Given : Recorded speed (in km/hr) of the 10 motorists are 47, 53, 49, 60, 39, 42, 55, 57, 52, 48
recorded average speed (in km/hr) of 10 motorists
= (47 + 53 + 49 + 60 + 39 + 42 + 55 + 57 + 52 + 48)/10
= 502/10
= 50.2 km/hr
Now, the instrument recorded 5 km/hr less in each case.
So, corrected average speed = 50.2 + 5 = 55.2 km/hr
Answer.
Answered by
8
Answer:
55.2kmhrrr is the correct answer
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