Question

the train accelerates from rest at a constant rate along a straight , horizontal track , it reaches a speed of 24m/s in 60s
calculate the train acceleration
please some one answer

Answer 1

Explanation:

train covers distance is - s=ut

.

s=24×60

s=1440

acceleration= s/t(square)

= 1440/(60×60)

= 0.4

Answer 2

Answer:

a=0.4m/s^2

Explanation:

We know a=(v-u)/t

Here,

u=0(train initially at rest)

v=24m/s

t=60

Now,

(24-0)/60=a

a=0.4m/s^2