The train starts from rest and accelerates uniformly at 10m/s-2 for 1 minute.Find the velocity and distance
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Explanation:
train starts from rest u =0
u=initial velocity
v=final velocity. 1 minute=60 seconds
u=0
v=?
acceleration a=10m/s2
a= v-u/t.
a=v-0/60
a=v/60
a=10
10=v/60
v=10×60
v=600.
distance s=?
s=ut+1/2at2
=0+1/2×10×60×60
=5×3600
=18,000
distance s=18,000
my answer will help you
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