Question

The train travels the first 30 km of 120 km track with a uniform speed of 30 km per hour what will the speed of the train to cover the remaining distance of a track so that its average speed is 60 km​

Answer 1

Answer:

90kmph

Explanation:

speed of first 30km, s1 = 30kmph

remaining distance to cover = 120-30=90km

speed of last 90km,s2 = x kmph

average speed = (s1+s2)/2

60 kmph = (30+x)/2

120 = (30+x)

x = 120-30

x=90 kmph