the train trawler at a speed of 25m/a ,brake are applied to stop the train at the acceleration of 0.5 m per square second. the distance traveled by the train in
a) 500m
b) 750
c) 625m
d) none
please fast
Answers
Answered by
2
- Initial velocity (u) = 25ms⁻¹.
- Final velocity (v) = 0ms⁻¹ [Because breaks are applied].
- Acceleration (a) = -0.5ms⁻² [It is negative because it is acting in the opposite direction]
- The distance (s) of the train.
Recall the three equations of motion:
It is apt to use the third formula because v, u and a is given and we need to find s.
Substitute.
∴DISTANCE IS 625 m.
Similar questions