Question

The train with speed of 90 kmh applies brakes to uniform acceleration of -0.5 ms .Find how far it goes before rest​

Answer 1

Answer:

$\boxed{\mathfrak{Distance \ travelled \ (s) = 625 \ m}}$

Given:

Initial speed (u) = 90 km/h = 25 m/s

Final speed (v) = 0 m/s (Rest)

Accelration (a) = -0.5 m/s²

Explanation:

$\rm From \: 3^{rd} \: equation \: of \: motion \: we \: have: \\ \boxed{ \bf{ {v}^{2} = {u}^{2} + 2as}}$

s → Distance travelled

By substituting values in the equation we get:

$\rm \implies {0}^{2} = {25}^{2} + 2( - 0.5)s \\ \\ \rm \implies 0 = 625 - 1s \\ \\ \rm \implies s = 625 \: m$