The train with speed of 90 kmh applies brakes to uniform acceleration of -0.5 ms .Find how far it goes before rest
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Answer:
Given:
Initial speed (u) = 90 km/h = 25 m/s
Final speed (v) = 0 m/s (Rest)
Accelration (a) = -0.5 m/s²
Explanation:
s → Distance travelled
By substituting values in the equation we get:
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