Question

The trajectory of a projectile launched from ground is given by the equation below. where x and y are the coordinate of the projectile on a rectangular system of axes.a) Find the initial velocity and the angle at which the projectile is launched.

Answer 1

Answer:

Equation of trajectory is given as

y=2x−9x2         ...(1)

Comparing with equation:

y=xtanθ−2μ2cos2θg.x2           ...(2)

We get;

tanθ=2

∴cosθ=51

Also, 2μ2cos2θg=9

⇒2×9×(51)210=u2

u2=925

⇒u=35m/s