Physics, asked by adiltanveer247, 11 months ago

The trajectory of projectile in a vertical plane is y=ax-bx^2,where a and b are constant.find the maximum height attained by it and the angle of projectio from the horizontal

Answers

Answered by kainatjaved160

0

Answer:

H = V ^ 2 sin^ 2©/2g

Explanation:

hope it is helpful

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