the transformation matrix to shift the center of the circle(x-3)^2+(y+5)^2=16 to the origin
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Given: (x-3)^2+(y+5)^2=16
To find: We have to find the transformation matrix to shift the center of the circle(x-3)^2+(y+5)^2=16 to the origin.
Solution:
This is the form of a circle. Use this form to discover the center and radius of the circle.
(x-h)^2 + (y-k)^2 = r^2
Match the values in this circle to those of the usual standard form. The variable r denotes the radius of the circle, h denotes the x-offset from the origin, and k denotes the y-offset from the origin.
r = 4
h = 3
k = 5
The center of the circle is discovered at ( h, k ).
Center: (3, 5)
These values express the important values for graphing and analyzing a circle.
Center: ( 3, 5 )
Radius : 4
So, the final answer is 4.
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