The transport number of nitrate ion in silver nitrate solution is 0.66, the transport
number of silver ion will be....
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Explanation:
Given equivalent conductivity is 120
Transport number t
Ag
+
is 0.48
For (NO
3
)
−
the transport number is 1−0.48=0.52
equivalent conductivity for ((NO
3
)
−
is 120×0.52=62.4
Ionic mobility
96500
62.4
=6.467×10⁴-
@ngel
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