The treatment of alkyl chloride with aqueous koh lead to formation of alcohol whereas presence of alc koh alkene is the major product why
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bcoz in form formation of neulceophile OH- takes place faster.... and Cl- also gets detached from alkyl chloride in an form..... but not in case of all form
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Hey !!
In aqueous solution, KOH is almost completely ionised to give OH⁻ ions which being a strong nucleophile brings about a substitution reaction on alkyl halides to form alcohols. In the aqueous solution, OH⁻ ions are highly hydrated. This reduces the basic character of OH⁻ ions which fail to abstract a hydrogen from the β-carbon of the alkyl chloride to form an alkene.
On the other hand, an alcoholic solution of KOH contains alkoxide (OR⁻) ions which being a much stronger base than OH⁻ ions preferentially eliminates a molecule of HCl from an alkyl chloride to form alkenes.
Hope it helps you !!
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