Question

The tree is broken by the wind.The top strikes thr ground at a distance of 1.5m from its base.If the tree has broken at a height of 2m from the ground, What is the height of the tree?
I want the correct answer.
Please​

Answer 1

Answer:

it's 4.5m

Step-by-step explanation:

by Pythagoras theorem

h² = p² + b²

so

2.5+2

4.5m

Answer 2

Given

• Tree strike ground at a distance of 1.5m from its base (Base)
• Tree has broken at a height of 2m (Perpendicular)

Explanation

Firstly, We have to find the distance from the point where tree broke to the point where tree's top touches Ground i.e. (Diagonal Distance)

For this We have to use Pythagoras theorem to find distance b/w them :-

$\maltese {\large{\pmb{\boxed{\underline{\sf{ (Diagonal)^2 = (Base)^2 + (Perpendicular)^2 }}}}}} \\ \\ \\ \colon\implies{\sf{ (Diagonal)^2 = (1.5)^2 + (2)^2 }} \\ \\ \\ \colon\implies{\sf{ (Diagonal)^2 = 2.25 + 4 }} \\ \\ \\ \colon\implies{\sf{ (Diagonal)^2 = 6.25 }} \\ \\ \\ \colon\implies{\sf{ (Diagonal) = \sqrt{6.25} }} \\ \\ \\ \colon\implies{\sf{ (Diagonal) = 2.5 \ m }}$

Therefore, The diagonally distance of tree is 2.5 m.

Now, We can add the Perpendicular distance in Diagonal Distance to find the Total Height of the Tree as:-

$\colon\implies{\sf{ Diagonal \ distance + Perpendicular \ distance }} \\ \\ \\ \colon\implies{\sf{ 2.5 + 2 }} \\ \\ \\ \colon\implies{\sf{ 4.5 \ m }}$

Hence,

• The height of the tree is 4.5 m.