Question

the triangle ABC,DE is parallel to BC,if AD=X,DB=X-2,AE=X+2 and EC=X-1,find X

Answer 1

Step-by-step explanation:

DE is parallel to BC

AD/BD = AE/EC

X/(X-2) = (X+2)/(X-1)

X(X-1) = (X-2) * (X+2)

X² - X = X² - 4

-X = -4

X = 4