Math, asked by ajaykeesari7, 2 days ago

The triangle ABC is defined by the vertices A=(0,7,10), B=(-1,6,6,) and C=(-4,9,6). Let D be the foot of the altitude from B to the side AC. Then BD is

Answers

Answered by NikBeanie
0

Answer:

Solution

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Correct option is B)

Given : A=(0,7,10),B=(−1,6,6) and C=(−4,9,6)

Position vector(P.V.) of AB is (−1,−1,−4)

⟹∣AB∣=

(−1)

2

+(−1)

2

+(−4)

2

=

18

P.V. of BC is (−3,3,0)

⟹∣BC∣=

(−3)

2

+3

2

+0

=

18

P.V. of AC is (−4,2,−4)

⟹∣AC∣=

(−4)

2

+2

2

+(−4)

2

=6

Now, D is the midpoint of AC

⟹D=(

2

0−4

,

2

7+9

,

2

10+6

)=(−2,8,8)

BD

=−

i

^

+2

j

^

+2

k

^

Answered by srivastavaujjwal733
0

Answer:

B

Step-by-step explanation:

Correct option is B)

Given : A=(0,7,10),B=(−1,6,6) and C=(−4,9,6)

Position vector(P.V.) of AB is (−1,−1,−4)

⟹∣AB∣= (−1)

2

+(−1)

2

+(−4)

2

=

18

P.V. of BC is (−3,3,0)

⟹∣BC∣=

(−3)

2

+3

2

+0

=

18

P.V. of AC is (−4,2,−4)

⟹∣AC∣=

(−4)

2

+2

2

+(−4)

2

=6

Now, D is the midpoint of AC

⟹D=(

2

0−4

,

2

7+9

,

2

10+6

)=(−2,8,8)

BD

=−

i

^

+2

j

^

+2

k

^

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