The triangle formed by the lines root 3x+y-2=0,root3x-y+1=0,y=0 is
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Use them in the linear equation... then draw graph for it, u get the answer
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Answer:
Point A is (2/3, 0), Point B is (-1/2, 0)
Step-by-step explanation:
We have two equations:
3x + y - 2 = 0
y = 2 - 3x ---- (1) The line passes through the origin, O.
3x - y + 1 = 0
y = 3x + 1 ---- (2) The line passes through the origin, O.
at y = 0 ---- (3)
Let lines at (1) and (2) intersect at A while lines at (2) and (3) intersect at B.
So y = 2 - 3x = 0 or x = 2/3, Point A is (2/3, 0).
y = 3x + 1 = 0, or x = -1/2. Point B is (-1/2, 0).
The distance AB = {2/3-(-1/2)} = 7/6.
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