The triangle PQR is inscribed in the circle x2 + y2 = 25. If Q = (3, 4) and R=(-4, 3) then angle QPR=
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Answer:
The given equation of circle is x
2
+y
2
=25
∴ Centre is (0,0) and r=5
Now,
OR=
(−4−3)
2
+(3−4)
2
=
49+1
=
50
=5
2
units
OQ=OR=5 units
cos∠QOR=
2OQ×OR
OQ
2
+OR
2
−QR
2
⇒cos∠QOR=
2×5×5
25+25−50
=0
⇒∠QOR=90
o
We know the angle subtended by an arc at the centre is double the angle subtended by same arc at any point on the circle.
Now, ∠QOR=2∠QPR
⇒90
o
=2∠QPR
⇒∠QPR=45
o
=
4
π
.
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