the triangle two side length are 18 and one side 10 and perimeter is 42 find the area
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Answer:
21√11 cm²
Step-by-step explanation:
Two sides length are given, we need to figure out the length of this side.
⇒Let x be length of third side
⇒Perimeter =42 cm
⇒18+10cm+x=42
⇒x=42−28=14 cm
⇒2s=42
⇒s=21 cm
⇒a=18,b=10,c=14
⇒A=
s(s−a)(s−b)(s−c)
⇒
21(21−18)(21−10)(21−14)
=
21×3×11×7
⇒A=21 √11cm²
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