Math, asked by dondee40631, 1 month ago

The triangle whose vertices are (0,0) (2.7,0) and (0,4.9) is

Answers

Answered by sundrikasingh
0

Answer:

The triangle is scalene triangle

Answered by HrishikeshSangha
0

Given:- The vertices (0,0) (2.7,0) and (0,4.9)

To find:- The type of the triangle

Solution:-

The given vertices are as (0,0) (2.7,0) and (0,4.9)

Consider A as (0,0) B as (2.7,0) and C as (0,4.9)

Now use the formula,

for A and B and subsititute the values,

AB = ((2.7-0)^2 - 0)^1/2 Calculating the values we get,

AB = 2.7 units

Similarly apply the given conditions for B and C

BC= ((2.7-0)^2 - 4.9^2)^1/2 Calculating the values we get,

BC = (31.3)^1/2

BC = 5.6 units

Similarly go for AC

AC = ((4.9-0)^2 - 0)^1/2 Calculating the values we get,

AC= 4.9units

Now from the results we can analyse that AB BC and Ac are having different lengths and hence it cannot be an equilateral triangle.

As AB not equal to BC not equal to AC hence we conclude that the triangle is a Scalene Triangle.

The given Triangle is Scalene.

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